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Solution for day 11 of #javascriptmas
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Solution for day 11 of #javascriptmas
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Solution for day 11 of #javascriptmas
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main.js
run
preview
console
function avoidObstacles(nums) {
for (let i = 1; i <= Math.max(...nums) + 1; i++) {
if (nums.every(x => x % i !== 0)) {
return i;
}
}
}



/**
* Test Suite
*/
describe('avoidObstacles()', () => {
it('returns minimal number of jumps in between numbers', () => {
// arrange
const nums = [5, 3, 6, 7, 9];
// act
const result = avoidObstacles(nums);

// log
console.log("result: ", result);

// assert
expect(result).toBe(4);
});
});
Console
"result: "
,
4
,
/index.html
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