function avoidObstacles(nums) {
    const largest = Math.max(...nums);
    
    for (let i = 1; i < largest + 1; i++) {
        if (nums.every(v => v % i !== 0)) {
            return i;
        }
    }
}



/**
* Test Suite 
*/
describe('avoidObstacles()', () => {
    it('returns minimal number of jumps in between numbers', () => {
        // arrange
        const nums = [5, 3, 6, 7, 9];
        
        // act
        const result = avoidObstacles(nums);

        // log
        console.log("result: ", result);
        
        // assert
        expect(result).toBe(4);
    });
});